Question

5×10^19 electron are passing per second through an area of cross section 1mm^2 perpendiculerty find the current a.6A b.8A c. 4A d.2A​

Answer 1

Answer:

current can be defined at the product of magnitude of charge times it's frequency.

di = ndq/dt = ndq.df where n is the number of electrons , q is the charge of one electron and dt is the time it takes to flow and df is the frequency of electrons passing through the conductor.

accordingly you don't need to use the cross sectional data provided in the question , it's redundant.

solution :

I = Ne/T = ( 5*10^19 x 1.6*10^-19c ) / 1s

thus , I = 8A.

hope this helps you.