Physics, asked by ItzInnocentPrerna, 2 months ago

ᎬᏞᏞᎾ ᏴᏌᎠᎠᏆᎬᏚ ❤❤

ᴀɴ ᴇʟᴇᴄᴛʀᴏɴ ᴍᴏᴠɪɴɢ ᴡɪᴛʜ ᴀ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ 5 × 10⁴ ᴍ/s ᴇɴᴛᴇʀs ɪɴᴛᴏ ᴀ ᴜɴɪғᴏʀᴍ ᴇʟᴇᴄᴛʀɪᴄ ғɪᴇʟᴅ & ᴀᴄǫᴜɪʀᴇs ᴀ ᴜɴɪғᴏʀᴍ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴏғ 104 ᴍ/s² ɪɴ ᴛʜᴇ ᴅɪʀᴇᴄᴛɪᴏɴ ᴏғ ɪᴛs ɪɴɪᴛɪᴀʟ ᴍᴏᴛɪᴏɴ.
★ ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴛɪᴍᴇ ɪɴ ᴡʜɪᴄʜ ᴛʜᴇ ᴇʟᴇᴄᴛʀᴏɴ ᴡᴏᴜʟᴅ ᴀᴄǫᴜɪʀᴇ ᴀ ᴠᴇʟᴏᴄɪᴛʏ ᴅᴏᴜʙʟᴇ ᴏғ ɪᴛs ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ.
★ ʜᴏᴡ ᴍᴜᴄʜ ᴅɪsᴛᴀɴᴄᴇ ᴛʜᴇ ᴇʟᴇᴄᴛʀᴏɴ ᴡᴏᴜʟᴅ ᴄᴏᴠᴇʀ ɪɴ ᴛʜɪs ᴛɪᴍᴇ ?

ɳσ รραɱ

30 ❤ = เɳɓσא ​


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Answers

Answered by mohit810275133
7

Explanation:

HEY MATE ........

initial \: velocity \: of \: the \: electron \: is \: \\  \\  u = 5 \times  {10}^{4} m |sec |  \\  \\ acceleration \: of \: the \: electron \: is \: \\  \\  a =  {10}^{4} m {sec}^{2}  \\  \\ from \: first \: eqn. \: of \: motion \\  \\ v = u + at \\  \\ 2u = u + at \\  \\ t =  \frac{u}{a}  \\  \\ \implies  \frac{(5 \times  {10}^{4} }{ {10}^{4} }  \\  \\ \implies5sec

HOPE IT HELPS YOU

Answered by manjhisashikant088
3

Answer:

5sec

Explanation:

Initial

velocity of the electron is

U=5×104m/sec

acceleration of the electro

a=104msec

from first eyn of mortion

U=U

24=u+at

+=u/a

5×104/104

=5sec

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