Question

5,11,17,...;9th term

26,22,18,...;40th term

103rd term of the arithmetic sequence if a¹=-5 and =-4​

Answer 1

Answer:

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Answer 2

Solution :-

(1) 5,11,17,_____ 9th term .

→ First term = a = 5

→ Common difference = d = a2 - a1 = 11 - 5 = 6

So,

→ T(n) = a + (n - 1)d

then,

→ T(9) = 5 + (9 - 1)6

→ T(9) = 5 + 8 * 6

→ T(9) = 5 + 48

→ T(9) = 53 (Ans.)

Hence, 9th term of given AP series is 53 .

(2) 26,22,18,________ 40th term

→ First term = a = 26

→ Common difference = d = a2 - a1 = 22 - 26 = (-4)

So,

→ T(n) = a + (n - 1)d

then,

→ T(40) = 26 + (40 - 1)6

→ T(40) = 26 + 39 * (-4)

→ T(40) = 26 - 156

→ T(40) = (-130) (Ans.)

Hence, 40th term of given AP series is (-130) .

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