Question

5. 13 A127
is a stable isotope; then, 13 A129 is expected to disintegrate by:
a) a - emission
b) B - emission
c) Positron emission
d) Proton emission
​

Answer 1

Answer:

. 13 A127

is a stable isotope; then, 13 A129 is expected to disintegrate by B-emission