Question

5+ За – 14а^2 factorise​

Answer 1

Answer:

Let a = x

$5 + 3x - 14 {x}^{2} \\ = - (14 {x}^{2} - 3x - 5) \\ = - (14 {x}^{2} - 10x + 7x - 5) \\ - (2x(7x - 5) + 1(7x - 5)) \\ = - (7x - 5)(2x + 1) \\ = (5 - 7x)(2x + 1)$

so factors become (5 - 7a)(2a + 1)

Answer 2

Step-by-step explanation:

5+3a-14a^2

(arranging given polynomial)

-14a^2+3a+5

-14a²-10a+7a+5

-2a(7a+5)+1(7a+5)

(-2a+1)(7a+5)