Math, asked by Anshul996655, 11 months ago

5.15. A swimming pool 100 m long and 40 m wide is 1 m
deep at the shallow end and 5 m at the deep end.
Find the volume of water contained in the pool.​

Answers

Answered by JunaidMirza
2

Answer:

24000 m³

Step-by-step explanation:

Volume = Length × Breadth × Depth

At shallow end

V1 = 100 m × 40 m × 1 m = 4000 m³

At deep end

V2 = 100 m × 40 m × 5 m = 20000 m³

Total volume = V1 + V2

= 4000 m³ + 20000 m³

= 24000 m³

Volume of water is therefore 24000 m³

Answered by Manognan
2

Answer:12,000 m^3

Step-by-step explanation:

Divide the pool into a cuboid of 1m deep.

Volume of that cuboid is

100 x 40 x 1 = 4,000m^3 .……1

The volume of the down part of the pool is

1/2 x 100 x 40 x 4 (height is 5-1 =4)

=8,000 m^3 ……2

1+2

=4,000+8,000

=12,000m^3

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