Math, asked by anupam227, 1 month ago

5^√16×5^√2 please answer ​

Answers

Answered by shreyanshyadav221
0

Answer:

Answer:

\begin{gathered} \\ \qquad \:\boxed{\begin{aligned}& \qquad \:\bf \: Seela \: age=10 \: years \qquad \: \\ \\& \qquad \:\bf \: Sonam \: age=40 \: years \\ \\\end{aligned}} \qquad \\ \\ \end{gathered}

Seelaage=10years

Sonamage=40years

Step-by-step explanation:

Let assume that

Seela present age be x years.

So,

Sonam present age be 4x years.

Five years ago,

Seela age was = x - 5 years

Sonam age was = 4x - 5 years

According to statement, five year ago Sonam was 7 times as old as Seela.

\begin{gathered}\sf \: 4x - 5 = 7(x - 5) \\ \\ \end{gathered}

4x−5=7(x−5)

\begin{gathered}\sf \: 4x - 5 = 7x - 35 \\ \\ \end{gathered}

4x−5=7x−35

\begin{gathered}\sf \: 4x - 7x = 5 - 35 \\ \\ \end{gathered}

4x−7x=5−35

\begin{gathered}\sf \: - 3x = - 30 \\ \\ \end{gathered}

−3x=−30

\begin{gathered}\sf\implies \: x = 10 \\ \\ \end{gathered}

⟹x=10

Hence,

Seela present age = 10 years

Sonam present age = 40 years

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