Math, asked by namsenomatlab, 19 days ago

5^2 / 10 =2500 / x then x =?​

Answers

Answered by ItzDinu
2

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The correct problem is given here. there is no leading - in the beginning.

\begin{gathered} + 5^{2x-1} - 25^{x-1} =2500 \\ \\ + 5^{2x-1} - 5^{2x-2} = 5^2 * 25 * 4\\ \\ + 5^{2x-1} [1 - 5^{-1}] = 5^4 * 2^2 \\ \\5^{(2x-1)} \frac{4}{5} = 5^4 2^2 \\ \\ 5^{2x-1} = 5^5 \\ 2x -1 = 5 \\ x = 3 \\ \end{gathered}

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Answered by TYKE
0

the \: answer \: is \:  \boxed {x = 3}

Step-by-step explanation:

 {5}^{2x - 1}  -  {25}^{x - 1}  = 2500

 {5}^{2x - 1}  -  {5}^{2x - 2}  = 2500

{5}^{2x - 1} (1 -  {5}^{ - 1} ) =  {5}^{2} ∗ 25∗4

 {5}^{(2x - 1)}  \frac{4}{5}  =  {5}^{4} ∗ {2}^{2}

 {5}^{(2x - 1)}  =  {5}^{4}  {2}^{2}  \times  \frac{5}{4}

 {5}^{(2x - 1)}  =  {5}^{5}

2x - 1 = 5

2x = 6

x = 3

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