5√2+3√3 and. 2√2-5√3.
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Step-by-step explanation:
Two easy methods to solve such questions:
By Inspection
Let the numbers be in general form “a root b”.
In “5 root 7” both “a” and “b” are greater than in “3 root 2” and “2 root 3”. So “5 root 7” is greatest.
In “3 root 2” and “2 root 3”, the two numbers are of the form “x root y” and “y root x”, respectively. So clearly, the number with greater integer as “a” will be greater, since “root t” <= “t” always.
Therefore “5 root 7” > “3 root 2” > “2 root 3”.
By Squaring
By squaring all the numbers, numbers become: 175, 18, 12
So order is 175>18>12.
Now if a^2 > b^2 > c^2, then a > b > c for all a,b,c > 0.
Therefore “5 root 7” > “3 root 2” > “2 root 3”.
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