Math, asked by sakakade11, 3 months ago

5^2÷3^3 rationalize the denominator ​

Answers

Answered by vaishnaviJha09
0

Answer:

5²÷3³

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Answered by pmpanghal
0

Answer:

We rationalise the denominator of (

3

2

5

5

2

3

) by multiplying its rationalising factor (3

2

+

5

) in the numerator and denominator as follows:

3

2

5

5

2

3

×

3

2

+

5

3

2

+

5

=

(3

2

5

)(3

2

+

5

)

(5

2

3

)(3

2

+

5

)

=

(3

2

)

2

−(

5

)

2

5

2

(3

2

+

5

)−

3

(3

2

+

5

)

=

(9×2)−5

(5×3

2×2

)+(5

2×5

)−(3

3×2

)−(

3×5

)

=

18−5

15

4

+5

10

−3

6

15

=

13

(15×2)+5

10

−3

6

15

=

13

30+5

10

−3

6

15

Hence,

3

2

5

5

2

3

=

13

30+5

10

−3

6

15

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