5-2√3/7-4√3 rationalise
Answers
Answered by
1
(5+2√3)/(7+4√3)=[(5+2√3)(7-4√3)]/[(7+4√3)(7-4√3)]
= (35-20√3+14√3-24)/(49-48) [∵ (a+b)(a-b)=a²-b²]
=11-6√3
Answered by
1
(5+2√3)/(7+4√3)=[(5+2√3)(7-4√3)]/[(7+4√3)(7-4√3)]
= (35-20√3+14√3-24)/(49-48) [∵ (a+b)(a-b)=a²-b²]
=11-6√3
Similar questions