Question

5+2√3 / 7+4√3 solve by rationalisig denominator​

Answer 1

Answer:

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Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

To Simplify:

• $\dfrac{5+2\sqrt{3}}{7+4\sqrt{3}}$

Solution:

$\implies \dfrac{5+2\sqrt{3}}{7+4\sqrt{3}}\\\\ \implies \dfrac{5+2\sqrt{3}}{7+4\sqrt{3}} \times \dfrac{7-4\sqrt{3}}{7-4\sqrt{3}} \\\\ \implies \dfrac{(5+2\sqrt{3})\times (7-4\sqrt{3})}{(7+4\sqrt{3})\times (7-4\sqrt{3})} \\\\ \implies \dfrac{35-20\sqrt{3}+14\sqrt{3}-24}{49-48} \\\\ \bf{\implies 11 - 6\sqrt{3}}$

Hope It helps!