Question

(5+2√-4) + (1-√-9) + (2+3i) (2-3i)

Answer 1

Answer:

19+i

Step-by-step explanation:

$(5+2\sqrt{-4}) + (1-\sqrt{-9})+(2+3i) (2-3i)$

Given:

$(5+2\sqrt{-4})+ (1-\sqrt{-9}) + (2+3i) (2-3i)$

$=(5+2\sqrt{4i^2})+ (1-\sqrt{9i^2}) + (2+3i) (2-3i)$

$=(5+2\sqrt{(2i)^2})+ (1-\sqrt{(3i)^2}) +(2^2-(3i)^2)$

$=(5+2(2i))+(1-3i) +(4-9i^2)$

$=(5+4i)+(1-3i) +(4-9(-1))$

$=6+i +(4+9)$

$=6+i +13$

$=19+i$