Question

√5+2 / √5-2 simplyfy and rationalise ​

Answer 1

Answer:

$\frac{ \sqrt{5} + 2 }{ \sqrt{5} - 2 } = > \frac{ \sqrt{5} + 2}{ \sqrt{5} - 2} \times \frac{ \sqrt{5} + 2}{ \sqrt{5} + 2}$

$\frac{( \sqrt{5} + 2)( \sqrt{5} + 2) }{( \sqrt{5} - 2)( \sqrt{5} + 2) } = \frac{ { (\sqrt{5} )}^{2} + {(2)}^{2} + (2 \times \sqrt{5} \times 2)}{ {( \sqrt{5} )}^{2} - {(2)}^{2} }$

$= > \frac{5 + 4 + 4 \sqrt{5} }{5 - 4}$

$= > \frac{9 + 4 \sqrt{5} }{1}$

$= > 9 + 4 \sqrt{5}$