(5, -2), (6, 4) and (7, -2) are vertices of which triangle Equilateral Right angled triangle Isosceles None
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Explanation:
Let the points be A(5,-2), B(6,4) and C(7,-2)..the distances between AB, BC and AC will determine the type of triangle.
AB=√(x2-x1)²+(y2-y1)².
= √(6-5)²+(4-(-2))²
=√(1)²+(6)²
=√1+36
=√37 units
BC=√(x2-x1)²+(y2-y1)².
=√(7-6)²+(-2-(4))²
=√1²+(-6)²
=√1+36
=√37 units
AC=√(x2-x1)²+(y2-y1)².
=√(7-5)²+(-2-(-2))²
=√2²+0²
=√2² or √4
=2 units
Now the distances between AB and BC are equal but AC is not equal to AB and BC. We know that in an isosceles triangle 2 sides are equal and one is not equal. So,these form a isosceles triangle.
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