Question

5.ײ+ 6× - 7 = 0 solve this guys...​

Answer 1

Answer:

${x}^{2} + 6x - 7 = 0 \\ \\ = > {x}^{2} + (7 - 1)x - 7 = 0 \\ \\ = > {x}^{2} + 7x - x - 7 = 0 \\ \\ = > x(x + 7) - 1(x + 7) = 0 \\ \\ = > (x + 7)(x - 1) = 0 \\ \\ either \: x + 7 = 0 \\ \\ = > x = - 7 \\ \\ or \: x - 1 = 0 \\ \\ = > x = 1$

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Answer 2

Answer:

HOPE IT HELPS

Step-by-step explanation:

Solve it by Quadratic Formula

=    $\frac{-b \frac{+}{}\sqrt{b^{2} - 4ac } }{2a}$

From the equation it can be observed that

a = 5

b = 6

c = -7

now put these value in the formula

before putting all the values, find out D

D = $\sqrt{b^{2} - 4ac }$

putting the values

= $\sqrt{6^{2} - 4 X 5 X -7$

= $\sqrt{36{} +140$

= $\sqrt[]{176}$

$4\sqrt{11}$

now put the value of D and other values in the first most equation

x = $\frac{- 6 \frac{+}{}4\sqrt{11} }{2 X 5}$

x =  $\frac{- 6 + 4\sqrt{11} }{10} , \frac{- 6 - 4\sqrt{11} }{10}$