Question

5)
2
An iron ring of cross-sectional area 6 cm' is wound with a wire of
100 turns and has a air gap of 2 mm. Calculate the magnetising
current required to produce a flux of 0.1 mwb if mean length of
magnetic path is 30 cm and relative permeability of iron is 470.
TTआयरन ऑफ़ प्रशिक्षण रेडियस 1 सैंटीमीटर स्क्वेयर इज ऑन द वेट ऑफ वायरस ​

Answer 1

To calculate the magnetizing current required to produce a flux of 0.1 mWb in the given iron ring, we can use the formula for magnetic flux:

• Φ = (N * I * μ * A) / l
• Where:
• Φ = Magnetic flux (in Weber, Wb)
• N = Number of turns in the wire
• I = Current flowing through the wire (in Amperes, A)
• μ = Relative permeability of the iron
• A = Cross-sectional area of the iron ring (in square meters, m²)
• l = Mean length of the magnetic path (in meters, m)
• Given:
• Number of turns (N) = 100
• Magnetic flux (Φ) = 0.1 mWb = 0.1 * 10^(-3) Wb
• Cross-sectional area (A) = 6 cm² = 6 * 10^(-4) m²
• Mean length of magnetic path (l) = 30 cm = 30 * 10^(-2) m
• Relative permeability of iron (μ) = 470
• Rearranging the formula, we can solve for the current (I):
• I = (Φ * l) / (N * μ * A)
• Substituting the given values:
• I = (0.1 * 10^(-3) * 30 * 10^(-2)) / (100 * 470 * 6 * 10^(-4))
• Simplifying:
• I = (0.003) / (282)
• I ≈ 0.0000106 A
• Therefore, the magnetizing current required to produce a flux of 0.1 mWb is approximately 0.0000106 Amperes or 10.6 μA.

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