Question

5/2 order reaction units of rate constant​

Answer 1

The unit of rate constant will be K = $Mol^{- 3/2}$$Litre^{3/2}$$Sec^{- 1}$

Given that;

The order of the reaction is 5/2

To find;

The unit of rate constant.

Solution;

"The rate of a chemical reaction is defined as the change in concentration of any reactant or product of the reaction in a particular time interval".

As we know,

For nth order; unit of rate constant may be derived by by the formula,

rate=K$[a] ^{n}$

K = $\frac{Rate }{(Reactant^){n} }$ where K = Unit of rate constant and n = order of the reaction

Now we have,

K = $Mol^{1 - n}$$Litre^{n - 1}$$Sec^{- 1}$

Putting the value of n = 5/2 in the above chemical equation we get,

K = $Mol^{1 - 5/2}$$Litre^{5/2 - 1}$$Sec^{- 1}$

K = $Mol^{- 3/2}$$Litre^{3/2}$$Sec^{- 1}$

Hence, The unit of rate constant will be K = $Mol^{- 3/2}$$Litre^{3/2}$$Sec^{- 1}$

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