Question

5-2 root 3/7-4root3 = a-b root 3

Answer 1

Answer:

Lhs = (5+2√3)/(7+4√3)= [(5+2√3)(7-4√3)]/[(7-4√3)(7+4√3)]=[35-20√3+14√3-24]/[7²-(4√3)²]=[11-6√3]/[49-48]=11-6√3

therefore

11-6√3 = a+b√3