5 + 2 root 3 by 7 + root 3 minus root 3 find a and b
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LHS=(5+2√3)(7+4√3)((7-4√3)(7+4√3)
(35-20√3+14√3-24) (7)2-4√3)2)
((11-6√3))(49-48)
(11-6√3)
therefore 11-6√3 =a+b√3
compare both sides a=11,b=6√3
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