Math, asked by karan20022005, 10 months ago

(5/(2-x))+((x-5)/(x+2))+((3x+8)+(x^2-4))=0

Answers

Answered by MaskedTitan
5

Answer:

5/(2-x) + (x-5)/(2+x) + (3x+8)/x²-4) = 0

=> (10+5x + 2x-x²-10+5x)/(4-x²) - (3x+8)/(4-x²)=0

=> (12x -x² -3x -8) / (4-x²) = 0

=> 9x -x² - 8 = 0

=> x² - 9x + 8 = 0

=> (x-8) ( x- 1) = 0

=> x = {8, 1 }

Answered by akibaftabsifmnil
2

Answer:

5/(2-x) + (x-5)/(2+x) + (3x+8)/x²-4) = 0

=> (10+5x + 2x-x²-10+5x)/(4-x²) - (3x+8)/(4-x²)=0

=> (12x -x² -3x -8) / (4-x²) = 0

=> 9x -x² - 8 = 0

=> x² - 9x + 8 = 0

=> (x-8) ( x- 1) = 0

=> x = {8, 1 }

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