Chemistry, asked by kunduheart143, 11 months ago

5. 200 ml decimolar H2SO4 and 300ml decimolar HCI
M
mixture is treated with M/5 NaOH solution. For
complete neutralisation of the acid mixture, volume
of NaOH required is
(1) 400 ml
(2) 250 ml
(3) 350 ml:
(4) 100 ml​

Answers

Answered by arunsomu13
4

Answer:

3) 350ml

Explanation:

Equivalence of acidic solution= Equivalence of basic solution

N₁V₁n₁+N₂V₂n₂=N₃V₃n₃

n=n-factor

N=normality

V=volume

1,2 and 3 subscript stands for H₂SO₄, HCl and NaOH respectively

(2)(0.2)(0.1)+(0.1)(1)(0.3)=(0.2)(V)(1)

V=0.07/0.3=0.350L=350ml

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Answered by Anonymous
0

Hello Friend..!!

The answer of ur question is..!!

Option.D

Thank you..!

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