Question

5(2t+1)-3(2r-1)=12-2(r-3)​

Answer 1

Step-by-step explanation:

r in (-oo:+oo)

(12/5)*(r-2) = (2/3)*(3*r-(2*(2*r-1))) // - (2/3)*(3*r-(2*(2*r-1)))

(12/5)*(r-2)-((2/3)*(3*r-(2*(2*r-1)))) = 0

(12/5)*(r-2)+(-2/3)*(3*r-2*(2*r-1)) = 0

12/5*(r-2)-2/3*(3*r-2*(2*r-1)) = 0

12/5*(r-2)-2/3*(3*r-2*(2*r-1)) = 0

46/15*r-92/15 = 0

46/15*r-92/15 = 0

46/15*r-92/15 = 0 // + 92/15

46/15*r = 92/15 // : 46/15

r = 92/15/46/15

r = 2

r = 2