Question

5^2x-1=(1/125)^x-3. FIND THE VALUE OF X
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Answer 1

Step-by-step explanation:

${5}^{2x - 1} = { \frac{1}{125} }^{x - 3}$

${5}^{2x - 1} = { \frac{1}{ {5}^{3} } }^{x - 3}$

${5}^{2x - 1} = { {5}^{ - 3} }^{(x - 3)}$

${5}^{2x - 1} = {5}^{ - 3x + 9}$

Since Bases Are same we can equate the exponents

2x-1 = -3x+9

5x = 10

x = 2

Hope It Helps ^_^