5^ 2x + 1 = 6*5^x - 1
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Answered by
12
Hey!!!!
Here's your answer =>=>
5 ^2x + 1 = 6 × 5 ^x - 1
5 ^2x + 1 / 5 ^x = 6 - 1
5 ^2x + 5 ^1 / 5 ^x = 5
5 ^2x - x = 5 / 5
5 ^x = 1
5 ^x = 5 ^0
x = 0
Hope it will help you ☆▪☆
Thanks ^_^
Here's your answer =>=>
5 ^2x + 1 = 6 × 5 ^x - 1
5 ^2x + 1 / 5 ^x = 6 - 1
5 ^2x + 5 ^1 / 5 ^x = 5
5 ^2x - x = 5 / 5
5 ^x = 1
5 ^x = 5 ^0
x = 0
Hope it will help you ☆▪☆
Thanks ^_^
Smile122:
Plz stop its disturbing...
Answered by
15
5^2x +1 = 6×5^x-1
5^2x+1/5^2x=6-1
5^2x+1/5^2x=5
5^2x-x=5/5
5^x=1
5^x=5^0
base same....
x=0
Hope this helps u....
✌✌✌
5^2x+1/5^2x=6-1
5^2x+1/5^2x=5
5^2x-x=5/5
5^x=1
5^x=5^0
base same....
x=0
Hope this helps u....
✌✌✌
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