Question

5 -(2x-1)(x-1)= (1-x)(2x-2)
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Answer 1

$\Large\purple{\textbf{\textsf{answer:}}}$

$\large\bf{To~solve:}$

$\tt{~~~~~~~~~5-(2x-1)(x-1)=(1-x)(2x-2)}$

$\tt{: \longrightarrow 5-(2x^{2}-2x-x+1)=({\cancel{2x}}~-2-2x^{2}~~{\cancel{-2x}})}$

$\tt{: \longrightarrow 5-(2x^{2}-3x+1)=-2x^{2}-2}$

$\tt{: \longrightarrow 5-2x^{2}+3x-1=-2x^{2}-2}$

$\tt{: \longrightarrow 5~~{\cancel{-2x^{2}}}+{\cancel{2x^{2}}}+3x=-2+1}$

$\tt{: \longrightarrow 5+3x=-1}$

$\tt{: \longrightarrow 3x=-1-5}$

$\tt{: \longrightarrow 3x=-6}$

$\tt{: \longrightarrow x={\dfrac{-6}{3}}}$

$\tt{: \longrightarrow x={\purple{\underline{\boxed{\bf -2}}}}}$

Answer 2

Answer:

$\tt5−(2x−1)(x−1)=(1−x)(2x−2)$

$\tt{: \longrightarrow 5-(2x^{2}-2x-x+1)=({\cancel{2x}}~-2-2x^{2}~~{\cancel{-2x}}}$

$\tt{: \longrightarrow 5-(2x^{2}-3x+1)=-2x^{2}-2}$

$\tt{: \longrightarrow 5-2x^{2}+3x-1=-2x^{2}-2}$

$\tt{: \longrightarrow 5~~{\cancel{-2x^{2}}}+{\cancel{2x^{2}}}+3x=-2+1}$

$\tt{: \longrightarrow 5+3x=-1}:⟶5+3x=−1$

$\tt{: \longrightarrow 3x=-1-5}:⟶3x=−1−5$

$\tt{: \longrightarrow 3x=-6}:⟶3x=−6$

$\tt{: \longrightarrow x={\dfrac{-6}{3}}}:⟶x=$

$\tt{: \longrightarrow x={\purple{\underline{\boxed{\bf -2}}}}}:⟶x=$