Question

5))2y2 + 9y + 10 = 0
Let's learn​

Answer 1

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$2 {y}^{2} + 9y + 10 = 0$

$2 {y}^{2} + 4y + 5y + 10 = 0$

$2y(y + 2) + 5(y + 2) = 0$

$(y + 2)(2y + 5) = 0$

SO, THERE ARE TWO POSSIBILITIES:

$y = - 2$

OR

$y = \frac{ - 5}{2}$

Answer 2

use the quadraticformula

(1)

$y \: = - b + b { }^{2} - 4ac \div 2a$

once in standard form identity a, b and c from the original equation and plug them into the quadratic formula

2y² + 9y + 10 = 0

a=2

b=9

c= 10

$y \: = - 9 + \sqrt{9 {}^{2} } - 4.2.10 \: \div 2.2$ (2) simplify

Evaluate the exponent

multiply the numbers

subtract the number

Evaluate the square root

multiply the number

y= -9 + 1 / 4

to slove for the unknown variable separate into two equation: one with a plus and the other with a minus

y= -9 + 1/ 4

y = -9-4 / 4

rearrange and insulate the variable to find each Solution

y= -2

y= -5/2

Solution

y= -2

y= -5/2

hope its help you