Physics, asked by amarachetan, 11 months ago

(5√3-10t)=±5 solve for it
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Answers

Answered by Ravingston
1

Answer:(√3-1)/2=t or t=(√3+1)/2

Explanation:let we take (5√3-10t)=+5

5√3-5=10t

Take 5 as common in LHS

5(√3-1)=10t

Therefore,

t=:(√3-1)/2

On the other hand we take,

(5√3-10t)=-5

(5√3+5)=10t

Take 5 as common in LHS,

5(√3+1)=10t

Therefore,

t=(√3+1)/2

Hope this find helpful for you

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