Question

5 - [3 - {2- (2 x (-3) + 1) + (3-5)}]
please solve this answer whose answer will come first and correct answer i will make him/her the bbrainliest please

Answer 1

Answer:

Rule of Bodmas!!

Rule of Bodmas!!First you have to use :-

Rule of Bodmas!!First you have to use :-Big Bracket [ ]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]= 5-[3-{(2-(-5)+(3-5)}]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]= 5-[3-{(2-(-5)+(3-5)}]= 5-[3-{7-2}]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]= 5-[3-{(2-(-5)+(3-5)}]= 5-[3-{7-2}]= 5-[3-5]

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]= 5-[3-{(2-(-5)+(3-5)}]= 5-[3-{7-2}]= 5-[3-5]= 5+2

Rule of Bodmas!!First you have to use :-Big Bracket [ ]Middle Bracket { }Small Bracket ( )Division ÷Multiplication ×Addition +Subtraction -Now come to question :-= 5-[3-{2-(2X(-3)+1)+(3-5)}]= 5 - [3-{2-(-6+1)+(3-5)}]= 5-[3-{(2-(-5)+(3-5)}]= 5-[3-{7-2}]= 5-[3-5]= 5+2= 7 ans.

Answer 2

Correct answer is7.

5 - [3 - {2- (2 x (-3) + 1) + (3-5)}] = 7

Simplify this equation using BODMAS rule -

Simplify the brackets,

=>5-[3-{2-(-6+1)+(3-5)}]

Distribute,

=>5-[3-{2-(-5)+(3-5)}]

Subtract the numbers,

=>5-[3-{(2+5)+(-2)}]

Add the numbers, Rearrange terms

=>5-[3-{(7)+(-2)}]

Add the numbers,

=>5-[3-5]

=>5-(-2)

=>5+2

Add the numbers,

=>7

5 - [3 - {2- (2 x (-3) + 1) + (3-5)}] = 7

Rules to simplify the expression using BODMAS rule are as follows,

• First, simplify the brackets.
• Solve the exponent or root terms.
• Perform division or multiplication operation (from left to right)
• Perform addition or subtraction operation (from left to right)

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