Question

5√3+2√27-1/√3
ko saral kijiye
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Answer 1

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Answer 2

firstly √27 mein se 3 bhr lao then 3√3 ho jaega. Now all the terms have common√3 so write like this :

5√3+(2*3√3)-1√3

i.e. (5+6-1)√3

i.e.according to BODMAS RULE it will be

10*√3≅10 * 1.732

so u will have ≅17.32

hope u understood ....

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