Question

5/3(2y-1)=(3y-5) pls answer this someone​

Answer 1

Answer:

5/3(2y-1)=3y-5

We move all terms to the left:

5/3(2y-1)-(3y-5)=0

Domain of the equation: 3(2y-1)!=0

y∈R

We get rid of parentheses

5/3(2y-1)-3y+5=0

We multiply all the terms by the denominator

-3y*3(2y-1)+5*3(2y-1)+5=0

Wy multiply elements

-9y^2(2+15y(2+5=0