5+3√3÷7+4√3=a+b√3
help please
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The answer is simple yaar!!!
LHS = (5 + 2√3 ) / ( 7 + 4√3 )
rationalize the denominator
= (5 + 2√3 ) ( 7 - 4√3 ) / [ ( 7 + 4√3 ) ( 7 - 4√3 )
= [ 5 ×7 - 5 × 4√3 + 2√3 × 7 - 2√3 × 4√3 ] / [ (7 )² - (4√3 )² ]
here we used ( x + y ) (x - y ) = x² - y² identity
= [35 -20√3 + 14√3 -24 ] / [ 49 - 48 ]
= (11 - 6√3 )
therefore ,
LHS = RHS
11 - 6√3 = A - B√3
comparing both sides
A = 11,
B = 6
i hope this is useful to you.
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