Question

5 ^3 − 4 ^2 + 3 and 3 ^3 + 7 ^2 − 9​

Answer 1

Answer:

7+4

3

5+2

3

=a+b

3

Since rationalization of

c+

d

a+

b

=

c+

d

a+

b

×

c−

d

c−

d

Taking L.H.S.

By rationalization,

7+4

3

5+2

3

=

7+4

3

5+2

3

×

7−4

3

7−4

3

Since, {(a+b)(a−b)=a

2

−b

2

}

=

[(7)

2

−(4

3

)

2

]

(5+2

3

)×(7−4

3

)

=

49−16

3

3

35+14

3

−20

3

−8

3

3

=

49−48

35−

3

(14−8)−24

=

1

35−

3

(6)−24

=11−6

3

Hence, by comparing a = 11 & b = -6.

Answer 2

Answer:

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