Question

5+3 [4-2 { 4-2 (6-3) } ]
?????​

Answer 1

Answer:

96

Step-by-step explanation

=5+3(4-2(4-2*3))

=5+3(4-2(2*3))

=5+3(4-2*6)

=5+3(2*6)

=5+3*12

=8*12

=96

Answer 2

Here it is given that:

$5+3 [4-2 ( 4-2 (6-3) ) ]$

We have to find the value of the given expression,

For that, we have to use the rule of BODMAS:

Subtracting the terms 6 and 3 we get,

$=>5+3[4-2(4-2(3))]$

Now, by subtracting the terms 4 and 2 we get,

$=>5+3[2(2\times3)]$

Multiplying the terms 3 and 2 we get,

$=>5+3[2\times6]$

Again multiplying the terms 2 and 6 we get,

$=>5+3[12]$

By adding 5 and 3 we get,

$=>8\times 12$

Multiply both terms we get,

$=>96$

Hence, the required solution for $5+3 [4-2 ( 4-2 (6-3) ) ]$ is 96.