√5-√3 ÷ √5+√3 = 2x-√15 T.then find the value of x ?
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[r(5)–r(3)] ÷ [r(5)+r(3)] = 2x–r(15)
[(r(5)–r(3)]² ÷ [(r(5))²–(r(3))²] = 2x–r(15)
(5+3–2r(15))÷(5–3) = 2x–r(15)
(8–2r(15)) ÷ 2 = 2x–r(15)
4–r(15) = 2x–r(15)
2x = 4
x = 2
[(r(5)–r(3)]² ÷ [(r(5))²–(r(3))²] = 2x–r(15)
(5+3–2r(15))÷(5–3) = 2x–r(15)
(8–2r(15)) ÷ 2 = 2x–r(15)
4–r(15) = 2x–r(15)
2x = 4
x = 2
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