√5+√3/√5-√3=a+b√15 find a and b
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QUES: √5+√3/√5-√3 = a+b√15
SOLUTION :- Firstly rationalize the denominator of LHS.
(√5+√3/√5-√3)*(√5+√3/√5+√3)
= (√5+√3)^2/(√5)^2 - (√3)^2
= (√5)^2 + (√3)^2 + 2*√5*√3
= 5 + 3 + 2√15
= 8 + 2√15
Here given ,,
(√5+√3/√5-√3) = a+b√15
=> 8 + 2√15 = a+b√15
Now, clearly a= 8 and b= 2.
HOPE IT HELPS.....☺✌
HERE IS UR ANSWER ✅✅✅
QUES: √5+√3/√5-√3 = a+b√15
SOLUTION :- Firstly rationalize the denominator of LHS.
(√5+√3/√5-√3)*(√5+√3/√5+√3)
= (√5+√3)^2/(√5)^2 - (√3)^2
= (√5)^2 + (√3)^2 + 2*√5*√3
= 5 + 3 + 2√15
= 8 + 2√15
Here given ,,
(√5+√3/√5-√3) = a+b√15
=> 8 + 2√15 = a+b√15
Now, clearly a= 8 and b= 2.
HOPE IT HELPS.....☺✌
Anonymous:
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iska common kon krega
a=4,b=1 it is the answer
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no
tumhe nhi keh rha mein rrshita ko bol rha tha
ok
hor ji
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