Math, asked by scar123, 9 months ago

√5+√3/√5-√3.rationalise the denominator.​

Answers

Answered by brainly2107
1

Answer:

 \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  -  \sqrt{3} }

  = \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5} -  \sqrt{3}  } \times  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  +  \sqrt{3} }

  = \frac{( \sqrt{5}  +  \sqrt{3} )^{2} }{( \sqrt{5})^{2} - ( \sqrt{3} )^{2}   }

  = \frac{5 + 2 \sqrt{15}  + 3}{5 - 3}

 =  \frac{8 + 2 \sqrt{15} }{2}

 = {4 + \sqrt{15} }

Similar questions
Math, 4 months ago