Chemistry, asked by biakkim9168, 10 months ago

5.3 gram of anhydrous sodium carbonat dissolved in 500 m.l of the solution calculate the narmality of the solution

Answers

Answered by Priti2413

0

Answer:

150.1 N

Explanation:

Normality=(No.of grm equivalent ×1000)÷Vol

=0.1501 ×1000

=150.1

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