Question

5.3 One litre of an aqueous solution of glucose (molecular weight 180) contains 18 g of glucose. Calculate the strength of the solution in molarity​

Answer 1

Answer:

Given: One litre of an aqueous solution of glucose ( molecular weight 180 ) contains 18 g of glucose.

To find: Strength of the solution in molarity

Explanation: Given mass of glucose= 18 g

Molecular weight of glucose= 180 g

Let number of moles of glucose in solution be denoted as n.

Then, n = Given mass of glucose / Molecular mass of glucose

= 18/ 180

= 0.1 moles

Volume of solution ( in Litres) = 1 L

Molarity= Number of moles/ Volume ( in L)

= 0.1 / 1

= 0.1 M

Therefore, the strength of the solution in molarity is 0.1 M.