√5+3√x=3 then value of x is?
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![\sqrt{5} + 3 \sqrt{x} = 3 \\ \\ \sqrt{x } = \frac{3 - \sqrt{5} }{3} \\ \\ on \: squaring \: both \: side we \: have: \\ \\ \\ {x} = {( \frac{3 - \sqrt{5} }{3}) }^{2} \\ \\ {x} = \frac{9 + 5 - 6 \sqrt{5} }{9} \\ \\ x = \frac{14 - 6 \sqrt{5} }{9} \sqrt{5} + 3 \sqrt{x} = 3 \\ \\ \sqrt{x } = \frac{3 - \sqrt{5} }{3} \\ \\ on \: squaring \: both \: side we \: have: \\ \\ \\ {x} = {( \frac{3 - \sqrt{5} }{3}) }^{2} \\ \\ {x} = \frac{9 + 5 - 6 \sqrt{5} }{9} \\ \\ x = \frac{14 - 6 \sqrt{5} }{9}](https://tex.z-dn.net/?f=+%5Csqrt%7B5%7D++%2B+3+%5Csqrt%7Bx%7D++%3D+3+%5C%5C++%5C%5C++%5Csqrt%7Bx+%7D++%3D++%5Cfrac%7B3+-++%5Csqrt%7B5%7D+%7D%7B3%7D++%5C%5C++%5C%5C+on+%5C%3A+squaring++%5C%3A+both+%5C%3A+side+we+%5C%3A+have%3A++%5C%5C++%5C%5C++%5C%5C++%7Bx%7D+%3D++%7B%28+%5Cfrac%7B3+-++%5Csqrt%7B5%7D+%7D%7B3%7D%29+%7D%5E%7B2%7D++%5C%5C++%5C%5C++%7Bx%7D+%3D++%5Cfrac%7B9+%2B+5+-+6+%5Csqrt%7B5%7D+%7D%7B9%7D++%5C%5C++%5C%5C+x+%3D++%5Cfrac%7B14+-+6+%5Csqrt%7B5%7D+%7D%7B9%7D+)
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