Math, asked by sagarrohan549, 6 months ago

(5/3 xy) x (- 9/10) x^2y^3​

Answers

Answered by rakeshkushwaha379057
0

Answer:

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Answered by Anonymous
3

Step-by-step explanation:

Solution:

6x-5y=30

Put the value of x = 0 in the equation 6x - 5y = 30.

6 × 0 - 5y = 30

-5y = 30

-5y/-5 = 30/-5

y = -6

(0, -6)

Put the value of y = 0,

6x - 5 × 0 = 30

6x = 30

6x/6 = 30/6

x = 5

(5, 0)

Put the value of x = 3,

6 × 3 - 5y = 30

18 - 5y = 30

18 – 18 – 5y = 30 – 18

-5y = 12

-5y/-5 = 12/-5

y= -12/5

(3, -12/5)

Put the value of y = -2,

6x – 5(-2) = 30

6x + 10 = 30

6x + 10 – 10 = 30 – 10

6x = 20

6x/6 = 20/6

x = 10/3

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