Math, asked by gurdeepkaur511, 10 months ago

5-(3a^2-2a)(6-3a^2+2a) pls solve by factorization method ​

Answers

Answered by Natsukαshii
0

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Answered by BrainlyIAS
3

Answer:

(a - 1) (3a + 1) (a + 1) (3a - 5)

Step-by-step explanation:

5 - (3a^2 - 2a) (6 - 3a^2 + 2a)

So,

5 - (3a^2 - 2a) (6 - 3a^2 + 2a)

= 5 - m (6 - m)

where  m = 3a^2 - 2a

= 5 - 6m + m^2

= m^2 - 6m + 5

= m^2 - m - 5m + 5

= m (m - 1) - 5 (m - 1)

= (m - 1) (m - 5)

= (3a^2 - 2a - 1) (3a^2 - 2a - 5) ,

since  m = 3a^2 - 2a

=( (3a^2 - 3a + a - 1)

(3a^2 + 3a - 5a - 5))

= (3a (a - 1) + 1 (a - 1))

(3a (a + 1) - 5 (a + 1))

= (a - 1) (3a + 1) (a + 1) (3a - 5) ,

Hope it helps u and mark brainliest plz

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