5-(3a^2-2a)(6-3a^2+2a) pls solve by factorization method
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Answer:
(a - 1) (3a + 1) (a + 1) (3a - 5)
Step-by-step explanation:
5 - (3a^2 - 2a) (6 - 3a^2 + 2a)
So,
5 - (3a^2 - 2a) (6 - 3a^2 + 2a)
= 5 - m (6 - m)
where m = 3a^2 - 2a
= 5 - 6m + m^2
= m^2 - 6m + 5
= m^2 - m - 5m + 5
= m (m - 1) - 5 (m - 1)
= (m - 1) (m - 5)
= (3a^2 - 2a - 1) (3a^2 - 2a - 5) ,
since m = 3a^2 - 2a
=( (3a^2 - 3a + a - 1)
(3a^2 + 3a - 5a - 5))
= (3a (a - 1) + 1 (a - 1))
(3a (a + 1) - 5 (a + 1))
= (a - 1) (3a + 1) (a + 1) (3a - 5) ,
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