Question

5(3a-4) =7(6a+3)-11 please give the answer

Answer 1

$5(3a-4)=7(6a+3)\\\\15a-20=42a+21\\-27a=41$

$a=\frac{-41}{27}$

Answer 2

Answer:

a = -10/9  

Step-by-step explanation:

5(3a-4) = 7(6a +3 ) -11

(15a-20) = (42a + 21) -11

15a -20 = 42a +21 -11      -------------  removing brackets

-20 -21 + 11 = 42a -15a -----------------  transposing..

-30 =  27a   ----------------  subtracting like terms

-30/27 =a    ---------------------  transposing

-10/9 =a

a = -10/9