Question

5(3a + b)square-2 + 6(3a + b) - 8​

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\blue{\:\:\:Given:-\:\:\:\:\:}}$

$\sf 5(3a+b){}^{2}+6(3a+b)-8$

• let (3a+b)=y

Then

$\sf\underline{\pink{\:\:\:A.T.Q:-\:\:\:\:\:}}$

$\sf \implies 5y{}^{2}+6y-8\\ \\ \sf\implies 5y{}^{2} +(10-4)y-8\\ \\ \sf\implies 5y{}^{2}+10y-4y-8\\ \\ \sf\implies 5y(y+2)-4(y+2)\\ \\ \sf\implies (y+2)(5y-4)$

• Now put the value of y

• which is 3a+b

$\sf\implies( 3a+b+2)[5(3a+b)-4]\\ \\ \sf\implies (3a+b+2)(15a+5b-4)$

$\underline{\boxed{\sf{\purple{(3a+b+2)(15a+5b-4)}}}}$