Question

5.3g and Na2CO3 was dissolved in 800gm of water ,calculate the molality of solution

Answer 1

Answer:

MARK AS BRAINLIEST

Explanation:

Mole of Na2CO3= 5.3/106= 0.05

Molality= mole of solute/mass of solvent(in kg)

So, molality= 0.05/0.8 = 1/16 = 0.0625 mol/kg

Answer 2

Answer:

MARK AS BRAINLIEST

Explanation:

Mole of Na2CO3= 5.3/106= 0.05

Molality= mole of solute/mass of solvent(in kg)

So, molality= 0.05/0.8 = 1/16 = 0.0625 mol/kg