Math, asked by shobhaprasad22721, 11 months ago

(5+3i)^3 in the form a+ib​

Answers

Answered by robertfernandes
4

Answer:

-10+18i

Step-by-step explanation:

Expand (5+3i)^3 according to (a+b)^3 formula

 {(a + b)}^{3}   =  \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3}

(5+3i)^3 = (5)^3 + 3(5)^2×3i + 3(5)×(3i)^2 + (3i)^3

= 125 + 45i - 135 - 27i ( i^2 = -1)

= -10+18i

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