5/3log300/T=2/3log2
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Answer:
approximately T=189.190
Step-by-step explanation:
5/3log300/T = 2/3log2
5/3(log300 - logT) = 2/3log2
5/3*3/2(log100*3 - logT) = log 2
5/2(log10^2 + log3 - logT) = log 2
5/2(2log10 + log3 - logT) = log2
5/2 (2+0.4771 - logT) = 0.3010
5/2*2.4771 - 5/2 logT = 0.3010
-5/2 logT =(0.6010 - 12.3855)/2
-5logT = - 11.3845
logT = 11.3845/5
logT = 2.2769
T = 189.190
approximately
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