Question

5/3log300/T=2/3log2​

Answer 1

Answer:

approximately T=189.190

Step-by-step explanation:

5/3log300/T = 2/3log2

5/3(log300 - logT) = 2/3log2

5/3*3/2(log100*3 - logT) = log 2

5/2(log10^2 + log3 - logT) = log 2

5/2(2log10 + log3 - logT) = log2

5/2 (2+0.4771 - logT) = 0.3010

5/2*2.4771 - 5/2 logT = 0.3010

-5/2 logT =(0.6010 - 12.3855)/2

-5logT = - 11.3845

logT = 11.3845/5

logT = 2.2769

T = 189.190

approximately