5(3x+1)²+6(3x+1)-8=0
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Answered by
17
Answer:
Let (3x+1) be a.
According to the question,
Putting a= (3x+1), we get.....
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Answered by
0
Answer:
5(3x+1)^2 + 6(3x+1) -8 =0
5(9x^2 +6x +1) + 18x+6 -8 =0
45x^2 +30x+5 +18x -2 =0
45x^2 +48x+3 =0
3(x+1) + (15x+1)
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