Question

5/3x-1=3/12 + 4x solve the linear equation and find x​

Answer 1

Answer:

ANSWER:

Disclaimer: There is error in the Q. In (II) there should have been 2x - 3y = 12

5x + 3y = 9 -----(I)

2x - 3y = 12 ----- (II)

Add (I) and (II)

7x = 21

x = 3

Putting the value of x = 3 in (I) we get

5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2

Thus, (x, y) = (3, -6).

Answer 2

Given:

$\dfrac{5}{3x - 1} = \dfrac{3}{12 + 4x}$

What To Do:

We have to find the value of x.

Solution:

$\dfrac{5}{3x - 1} = \dfrac{3}{12 + 4x}$

Using cross multiplication,

⇒ 5(12 + 4x) = 3(3x - 1)

Solve the brackets,

⇒ 60 + 20x = 9x - 3

Take 3 to LHS and 20x to RHS,

⇒ 60 + 3 = 9x - 20x

Solve the terms,

⇒ 63 = -11x

Take 11 to LHS,

⇒ $\dfrac{63}{11} = -x$

Take the minus sign to LHS,

⇒ $-\dfrac{63}{11} = x$

∴ Therefore the value of x is $-\dfrac{63}{11}$.