Question

5 - (3x^2 - 2x) (6 - 3x^2 + 2x)​

Answer 1

Step-by-step explanation:

5-(3x2-2x)(6-3x2+2x)

Final result :

(3x + 1) • (x + 1) • (x - 1) • (3x - 5)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

5-(((3•(x2))-2x)•((6-3x2)+2x))

Step 2 :

Equation at the end of step 2 :

5 - ((3x2 - 2x) • (-3x2 + 2x + 6))

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

3x2 - 2x = x • (3x - 2)

Trying to factor by splitting the middle term

4.2 Factoring -3x2 + 2x + 6

The first term is, -3x2 its coefficient is -3 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +6

Step-1 : Multiply the coefficient of the first term by the constant -3 • 6 = -18

Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is 2 .

-18 + 1 = -17

-9 + 2 = -7

-6 + 3 = -3

-3 + 6 = 3

-2 + 9 = 7

-1 + 18 =